CS:GO Zoom Sensitivity

[bIackbear]

I've read this forum: https://www.reddit.com/r/GlobalOffensive/comments/43urd4/why_0818933027098955175_is_the_best_zoom/. I don't get it how he came up with these numbers. I get his method, but there's one thing I don't get.

He says:"arctan( 4/3 * tan( vertical_zoom_fov / 2) ) / arctan( 4/3 * tan( vertical_hip_fov / 2 ) ) = 0.3639702342662023." If I calculate this with the by myself, I get ±  57.62. (vFOV of CS:GO)

What did I do wrong?

Edited February 18, 2018 by bIackbear

[DPI Wizard]

You must also divide by the FOV difference: http://www.wolframalpha.com/input/?i=(tan(40degrees%2F2))%2F(tan(90degrees%2F2))%2F(40%2F90)

This is the same as Monitor Distance 0% btw: